Table 1.

Summary of eigenvalue analysis on the simplest bistable system [41]

	Solution 1	Solution 2	Solution 3
Steady States (x, y)	(0,0)	(2, 0.5)	(6, 4.5)
Jacobian $\mathbf{J}$	$\left(\begin{array}{cc}-1.5& 16\\ 0& -8\end{array}\right)$	$\left(\begin{array}{cc}-6& 14\\ 4& -8\end{array}\right)$	$\left(\begin{array}{cc}-18& 10\\ 12& -8\end{array}\right)$
Eigenvalues $({\lambda }_1,{\lambda }_2)$	$(-1.5,-8)$	$(-14.5,0.54)$	$(-25.04,-0.95)$
Stability Property	Stable	Saddle node	Stable

For each steady state solution, the corresponding Jacobian, eigenvalues, and stability are listed. There are two stable steady states, which make this system bistable