Skip to main content
. 2023 Dec 5;23:1190. doi: 10.1186/s12885-023-11693-6

Table 3.

Univariable and multivariable Cox regression analyses on risk factors of overall survival

Variables HR comparison UV HR (95% CI) UV P MV HR (95% CI) MV P
Age > 55 vs. ≤55 years 0.867 (0.762–0.986) 0.030 NS 0.981
Gender Male vs. female 1.024 (0.856–1.225) 0.795
Diabetes Present vs. absent 1.061 (0.856–1.316) 0.588
Hypertension Present vs. absent 0.963 (0.814–1.140) 0.663
HBsAg Positive vs. negative 1.113 (0.922–1.343) 0.266
HCVAb Positive vs. negative 0.873 (0.494–1.544) 0.641
Child-Pugh B vs. A 1.569 (1.261–1.952) < 0.001 1.377 (1.101–1.723) 0.005
Cirrhosis Present vs. absent 0.862 (0.756–0.981) 0.025 NS 0.126
PLT < 100 vs. ≥100 109/L 1.076 (0.910–1.273) 0.389
Tumor number Multiple vs. solitary 2.437 (2.002–2.966) < 0.001 1.420 (1.209–1.668) < 0.001
Tumor diameter ≥ 10 vs. <10 cm 1.114 (1.099–1.129) < 0.001 1.527 (1.283–1.817) < 0.001
Tumor differentiation III/IV vs. I/II 2.279 (1.784–2.910) < 0.001 1.619 (1.253–2.092) < 0.001
Tumor capsule Incomplete vs. complete 1.397 (1.148–1.699) 0.001 1.065 (0.869–1.304) < 0.001
Tumor capsule None vs. complete 1.986 (1.589–2.482) < 0.001 1.491 (1.183–1.881) < 0.001
Satellite nodules Presence vs. absence 1.861 (1.635–2.118) < 0.001 1.236 (1.059–1.443) < 0.001
Intraoperative blood loss ≥ 800 ml vs. <800 ml 2.163 (1.724–2.713) < 0.001 1.334 (1.043–1.706) 0.021
Anatomical hepatectomy Yes vs. no 0.837 (0.726–0.964) 0.014 NS 0.511
Resection margin ≥ 1 cm vs. <1 cm 0.602 (0.525–0.689) < 0.001 0.699 (0.595–0.821) < 0.001
PACE risk score intermediate-risk vs. low-risk 1.725 (1.506–1.975) < 0.001 1.413 (1.226–1.628) < 0.001
PACE risk score high-risk vs. low-risk 3.974 (3.187–4.956) < 0.001 2.425 (1.891–3.109) < 0.001

Abbreviations: PACE, Prognostic implications of Alpha-fetoprotein and C-reactive protein Elevation; HBV, hepatitis B virus; HCV, hepatitis C virus; PLT, platelet; HR, hazard ratio; CI, confidence interval; UV univariable

Schoenfeld residuals test for proportional hazards assumption: met (P = 0.102)