Hs+δt
Hs		0	1
	0	$1-\frac{1}{{\tau }_{ON}}\bullet \delta t$	$\frac{1}{{\tau }_{ON}}\bullet \delta t$
	1	$\frac{1}{{\tau }_{OFF}}\bullet \delta t$	$1-\frac{1}{{\tau }_{OFF}}\bullet \delta t$