Algorithm 3 Angle Shutoff Method

Input:  ${\phi }_h\backslash {\phi }_v=0,d$ Output:  $A{n}_{Shuth}\backslash A{n}_{Shutv}$   1:repeat   2:    if $I({\phi }_h\backslash {\phi }_v)>Th$ then ${\phi }_{off}({\phi }_h\backslash {\phi }_v)={\phi }_{off}({\phi }_h\backslash {\phi }_v)+1$   3:        ${\phi }_h\backslash {\phi }_v={\phi }_h\backslash {\phi }_v+1$   4:    else   5:        ${\phi }_{off}({\phi }_h\backslash {\phi }_v)={\phi }_{off}({\phi }_h\backslash {\phi }_v)$   6:    end if   7:until ${\phi }_h=360$ \${\phi }_v=90$   8:$A{n}_{Shuth}=\{\frac{{\phi }_{off}\left(1\right)}{360},\frac{{\phi }_{off}\left(2\right)}{360},\dots ,\frac{{\phi }_{off}\left(360\right)}{360}\}$ \$A{n}_{Shutv}=\{\frac{{\phi }_{off}\left(1\right)}{90},\frac{{\phi }_{off}\left(2\right)}{90},\dots ,\frac{{\phi }_{off}\left(90\right)}{90}\}$