Empirical formula analysis.
| Component | C (%) | O (%) | H (%) |
|---|---|---|---|
| % | 61.90 | 28.57 | 9.59 |
| ÷Atomic mass | 61.90/12 | 28.57/16 | 9.59/1.0078 |
| ÷Smallest value | 5.16/1.79 | 1.79/1.79 | 9.523/1.79 |
| Ratio | 2.88 | 1 | 5.32 |
| Mass of C2.88H5.32O1 = 55.92 | |||
| Ratio of mass (504.7/55.92) = 9.02 | |||
| So the empirical formula, (C2.88H5.32O1)×9.02 = ∼C26H48O9 | |||