Abstract
The reactions between cellobiose and cellobiose oxidase were investigated by stopped-flow spectrophotometry. Under anaerobic conditions rapid reduction of the associated flavin is followed by slower reduction of cytochrome b. The kinetic difference spectra are reported. The rate of flavin reduction depends on the cellobiose concentration (with an apparent second-order rate constant of approx. 10(5) M-1.s-1) but reaches a rate limit of approx. 20 s-1. In contrast, the rate of cytochrome b reduction decreases at high cellobiose concentrations. Kinetic titrations of the flavin and cytochrome b moieties yield the stoichiometries of the separate reactions, i.e. the number of moles of cellobiose needed to fully reduce 1 mole of each redox component. The rate constant for cytochrome b reduction, unlike that for flavin reduction, increased with enzyme concentration, prompting the conclusion that any given cytochrome b centre is reduced preferentially by flavin groups in different molecules rather than by its partner flavin within the same monomer. These data are discussed in the context of a scheme that rationalizes them and accounts for the overall stoichiometry in which three two-electron donors (cellobiose molecules) reduce two three-electron acceptors (the flavin-cytochrome b of cellobiose oxidase).
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Selected References
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