Algorithm 3 Power Allocation Based on SCA and Dual Decomposition Methods

Input: ${\lambda }_{i,g}^{\mathrm{iter},k},\xi ,\psi ,\text{iter\_max},ϵ,D_i^g,R_{i,g}^k,\sigma ,i\in \mathcal{I},g\in \mathcal{G}$. Initialization: $a_{i,g}^k$ = $b_{i,g}^k$ = 1, $\mathsf{\Delta }\epsilon$ = $\mathsf{\Delta }{\epsilon }_2$ = 0.1, $p_{i,g}^k$ = $p_{\max }$, j = iter = 1, ${\mathbf{E}}_i^g$ = ${\mathbf{E}}_{i,g}^k=0$. 1:for $k=1$ to K do 2:   while $\mathsf{\Delta }>ϵ$ or $\mathrm{iter}\le \text{iter\_max}$ do 3:     Update $\mathrm{iter}=\mathrm{iter}+1$ 4:     Update $a_{i,g}^k$ according formula (26) 5:     Update $b_{i,g}^k$ according formula (27) 6:     Calculate $p_{i,g}^{*,k}=\exp \left({\overline{p}}_{i,g}^{*,k}\right)$ 7:     repeat 8:        $j=j+1$ 9:        Calculate ${\overline{p}}_{i,g}^k$ according to formula (38) 10:        Update $\left\{{\eta }_{i,g}^k\right\}$ according to formula (39) 11:        Update $\left\{{\varphi }_{i,g}^k\right\}$ according to formula (40) 12:     until $j\ge \text{iter\_max}$ 13:     Update $\mathsf{\Delta }=|F\left({\lambda }_{i,g}^{\mathrm{iter},k}\right)-F\left({\lambda }_{i,g}^{\mathrm{iter}-1,k}\right)|$ 14:   end while 15:   Obtain ${\mathbf{E}}_{i,g}^k$ according to formula (23) 16:   Update ${\mathbf{E}}_i^g={\mathbf{E}}_i^g+{\mathbf{E}}_{i,g}^k$ 17:end for Output: ${\mathbf{E}}_i^g={\mathbf{E}}_{i,g}^k/K$.