Table 4.
Power (%) of NF and STDT Tests of Size α=.001 to Detect Association between Disease and a Diallelic Polymorphism, with the Use of Genotypes for 100 Sib Pairs
Power for (%) |
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True Modela |
100 Discordant Sib Pairs |
80 Discordant Sib Pairs and 20 Affected Sib Pairs |
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Frequency of B1 | β | c1 | Test Statistic | c1=1 | c1=1/2 | c1=0 | c1=1 | c1=1/2 | c1=0 |
.2 | .25 | 1 | NF, Ψ=1 | 81 | 63 | 1 | 78 | 60 | 20 |
NF, Ψ=K/(1-K)b | 87 | 69 | 1 | 84 | 60 | 17 | |||
STDT | 81 | 68 | 0 | 61 | 40 | 0 | |||
.2 | .5 | 1/2 | NF, Ψ=1 | 84 | 90 | 22 | 81 | 85 | 20 |
NF, Ψ=K/(1-K) | 90 | 92 | 22 | 82 | 83 | 17 | |||
STDT | 82 | 87 | 5 | 61 | 71 | 0 | |||
.4 | .3 | 0 | NF, Ψ=1 | 2 | 70 | 93 | 1 | 70 | 91 |
NF, Ψ=K/(1-K) | 1 | 75 | 95 | 1 | 71 | 93 | |||
STDT | 0 | 53 | 81 | 0 | 29 | 62 | |||
.1 | .3 | 1 | NF, Ψ=1 | 72 | 66 | 1 | 81 | 71 | 1 |
NF, Ψ=K/(1-K) | 77 | 69 | 2 | 83 | 67 | 1 | |||
STDT | 72 | 65 | 0 | 69 | 60 | 0 | |||
.1 | .3 | 1/2 | NF, Ψ=1 | 83 | 86 | 9 | 86 | 88 | 13 |
NF, Ψ=K/(1-K) | 84 | 83 | 9 | 86 | 86 | 11 | |||
STDT | 81 | 81 | 0 | 68 | 70 | 0 | |||
.3 | .3 | 0 | NF, Ψ=1 | 1 | 39 | 79 | 0 | 47 | 85 |
NF, Ψ=K/(1-K) | 1 | 45 | 83 | 1 | 49 | 84 | |||
STDT | 1 | 20 | 58 | 0 | 15 | 44 | |||
.05 | .35 | 1 | NF, Ψ=1 | 72 | 67 | 0 | 78 | 68 | 1 |
NF, Ψ=K/(1-K) | 66 | 61 | 1 | 71 | 60 | 2 | |||
STDT | 63 | 61 | 0 | 38 | 32 | 0 | |||
.05 | .8 | 1/2 | NF, Ψ=1 | 86 | 88 | 5 | 77 | 78 | 7 |
NF, Ψ=K/(1-K) | 80 | 79 | 7 | 69 | 68 | 5 | |||
STDT | 77 | 76 | 0 | 44 | 50 | 0 | |||
.2 | .4 | 0 | NF, Ψ=1 | 0 | 26 | 61 | 0 | 34 | 81 |
NF, Ψ=K/(1-K) | 0 | 18 | 67 | 0 | 34 | 83 | |||
STDT | 0 | 4 | 24 | 0 | 11 | 31 |
P(y=1∣g=i)=0.1+ciβ, where y is an indicator for disease, g = number of B1 alleles in genotype, and c0=0, c1=1.
K is the population prevalence of the disease.