Figure 2.
Same as Fig. 1, except for R1 against R3 = I(3s23p3 2D3/2–3s23p3 2P1/2)/I(3s23p3 4S–3s23p3 2D3/2,5/2) = I(8500 Å)/I(5518 + 5538 Å).
Same as Fig. 1, except for R1 against R3 = I(3s23p3 2D3/2–3s23p3 2P1/2)/I(3s23p3 4S–3s23p3 2D3/2,5/2) = I(8500 Å)/I(5518 + 5538 Å).