(A) Fixation probability for n = {1, 2, 3, 4} predicted by Equation 36. N = 100 is assumed so that the probability of the neutral case is given by 1/(2nN) = 1/(200n). (B) Substitution rate for n = {1, 2, 3, 4} from Equation 38. The substitution rate is measured such that the rate is 1 under neutrality (note that the substitution rate per site per generation is identical to the mutation rate for any n).