Table 3.
Reaction | PW91 | OPBE | B3LYP | B3LYP* | Exp'tl | ||
---|---|---|---|---|---|---|---|
[5] O2)gas + H2)gas --> H2O2)gas | |||||||
−21.67 | −12.3 | −22.84 | −22.86 | −25.25 | |||
[6] H2O2)gas + H2)gas --> 2 H2O)gas | |||||||
−76.63 | −80.64 | −73.75 | −72.58 | −84.01 | |||
[7] O2)gas + 2 H2)gas --> 2 H2O)gas | |||||||
−98.3 | −93.01 | −96.59 | −95.45 | −109.3 | |||
[8] H2O2)gas + 2 e−(SHE) + 2 H+)aq --> 2 H2O)liq | |||||||
−80.69 | −84.84 | −77.87 | −74.04 | −88.11 | |||
[9] O2)aq + 4 e-(SHE) + 4 H+)aq --> 2 H2O)liq | |||||||
−106.28 | −101.16 | −104.68 | −103.54 | −117.4 | |||
[4] O2 )aq + 4 e- (from cyt c2+) + 8 H+)aq(pH7) --> 2 H2O)liq + 4 H+)aq(pH3) | |||||||
−27.97 | −22.85 | −26.37 | −25.23 | −38.7 |
In Eq. 8 and 9, pH = 0 and [O2]aq = 1 M. The free energy difference between Eq. 6 and Eq. 8 is due solely to the different standard states of H2O)gas (1 atm) vs. H2O)liq (55 M). Similarly, the free energy difference between Eq. 7 and Eq. 9 is due to the different standard states of O2)gas (1 atm) vs. O2)aq (1 M) and H2O)gas vs. H2O)liq.