Fig. 3.

Analytical power against frequency of Q₁ when P_Q2 = 0.5 at 1% significance level. P_A = 0.5; P_B = 0.5; D_AQ1 = {min(P_Q1, P_A) − P_Q1 P_A}/2; D_BQ2 = 0.05; heritabilities $h_{Q_1}^2=0.2;h_{Q_2}^2=0.2$; the sample size N = 100. Model notations are the same as in Figure 2.