Table 2.

Statistical values obtained by one-way ANOVA with repeated measures in the factors hole (active vs inactive) and experimental phase (acquisition, extinction, reinstatement) for each reinstatement condition

	Hole			Experimental phase
	F value	p value		F value	p value
Vehicle + hypocretin-1
Acquisition	F(1,8) = 40.981	<0.001	Active	F(3,24) = 22.582	<0.001
Extinction	F(1,8) = 3.573	NS	Inactive	F(3,24) = 1.854	NS
Saline	F(1,8) = 2.286	NS
Reinstatement	F(1,8) = 46.952	<0.001
SB334867 5 mg/kg + hypocretin-1
Acquisition	F(1,3) = 14.527	<0.05	Active	F(3,9) = 13.493	<0.01
Extinction	F(1,3) = 0.316	NS	Inactive	F(3,9) = 1.093	NS
Saline	F(1,3) = 0.231	NS
Reinstatement	F(1,3) = 3.000	NS
Antalarmin 30 mg/kg + hypocretin-1
Acquisition	F(1,3) = 37.686	<0.01	Active	F(3,9) = 9.007	<0.01
Extinction	F(1,3) = 7.046	NS	Inactive	F(3,9) = 1.487	NS
Saline	F(1,3) = 0.648	NS
Reinstatement	F(1,3) = 33.989	<0.05
Vehicle + footshock
Acquisition	F(1,13) = 69.835	<0.001	Active	F(2,26) = 20.561	<0.001
Extinction	F(1,13) = 0.021	NS	Inactive	F(2,26) = 4.140	<0.05
Reinstatement	F(1,13) = 16.369	<0.01
SB334867 5 mg/kg + footshock
Acquisition	F(1,5) = 24.400	<0.01	Active	F(2,10) = 12.330	<0.01
Extinction	F(1,5) = 13.900	<0.05	Inactive	F(2,10) = 5.648	<0.05
Reinstatement	F(1,5) = 1.327	NS
SB334867 10 mg/kg + footshock
Acquisition	F(1,6) = 18.157	<0.01	Active	F(2,12) = 9.241	<0.01
Extinction	F(1,6) = 14.611	<0.01	Inactive	F(2,12) = 11.882	<0.01
Reinstatement	F(1,6) = 8.392	<0.05
Antalarmin 30 mg/kg + footshock
Acquisition	F(1,5) = 62.701	<0.01	Active	F(2,10) = 19.355	<0.001
Extinction	F(1,5) = 247.353	<0.001	Inactive	F(2,10) = 0.823	NS
Reinstatement	F(1,5) = 21.250	<0.01