Skip to main content
. Author manuscript; available in PMC: 2011 Jun 1.
Published in final edited form as: J Am Stat Assoc. 2010 Jun;105(490):473–481. doi: 10.1198/jasa.2009.ap08387

Table 5.

Conditional distributions given the both parental genotypes are observed

Probability
Parental genotypes AA Aa aa Joint Probability
(AA, AA) 1 0 0 P(AA, AA) = 1
(AA, Aa) 1/2 1/2 0 P(Aa,AA)=1/2
P(Aa,Aa)=P(AA,AA)=1/4
(AA, aa) 0 1 0 P(Aa, Aa)=1
(Aa, Aa) 1/4 1/2 1/4 P(AA,aa)=1/8
P(Aa,Aa)=1/4
P(AA,AA)=P(aa,aa)=1/16
P(AA, Aa)=P(aa, Aa)=1/4
(Aa, aa) 0 1/2 1/2 P(Aa,aa)=1/2
P(Aa,Aa) = P(aa,aa) =1/4
(aa, aa) 0 0 1 P(aa, aa) =1