Table 5.
Conditional distributions given the both parental genotypes are observed
Probability |
||||
---|---|---|---|---|
Parental genotypes | AA | Aa | aa | Joint Probability |
(AA, AA) | 1 | 0 | 0 | P(AA, AA) = 1 |
(AA, Aa) | 1/2 | 1/2 | 0 | P(Aa,AA)=1/2 P(Aa,Aa)=P(AA,AA)=1/4 |
(AA, aa) | 0 | 1 | 0 | P(Aa, Aa)=1 |
(Aa, Aa) | 1/4 | 1/2 | 1/4 | P(AA,aa)=1/8 P(Aa,Aa)=1/4 P(AA,AA)=P(aa,aa)=1/16 P(AA, Aa)=P(aa, Aa)=1/4 |
(Aa, aa) | 0 | 1/2 | 1/2 | P(Aa,aa)=1/2 P(Aa,Aa) = P(aa,aa) =1/4 |
(aa, aa) | 0 | 0 | 1 | P(aa, aa) =1 |