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. 2010 Oct;186(2):493–503. doi: 10.1534/genetics.110.120105

TABLE 3.

Mutation rates for Mut2, Mut3, and Mut4 lines grown in bottlenecks for 160 generations

Base substitution mutations
Strain No. mutations % genome ≥7× coverage Genome Size (bp) adjusted Mutation rate (per base per gen ×10−9)
Mut2 6 41 9,898,136 3.8
Mut3 9 69 16,657,838 3.4
Mut4 13 84 20,279,107 4.0
Average 3.7
Single-nucleotide indel mutations in 5- to 13-nt HP tracts
Strain
No. mutations
No. HP tracts >7× coverage
Mutation rate (per HP tract/generation × 10−7)
Mut2 6 57,502 6.5
Mut3 15 99,714 9.4
Mut4 27 122,816 14
Average 10
Single-nucleotide indel mutations in 8- to 13-nt HP tracts
Strain
No. mutations
No. HP tracts >7× coverage
Mutation rate (per HP tract/generation × 10−7)
Mut2 4 2,820 89
Mut3 10 7,054 89
Mut4 19 8,696 140
Average 110

The base substitution mutation rate was determined by calculating the percentage of the genome in which at least sevenfold DNA sequencing coverage to unique regions was obtained. This was done because our statistical analysis did not have sufficient power to reliably detect heterozygous mutations in regions with lower coverage. This information was used to calculate the mutation rate on the basis of the following formula: (number of mutations)/(160 generations)/(adjusted genome size), with the diploid S. cerevisiae genome size determined as 24,141,794 bp (http://www.yeastgenome.org/). To obtain indel mutation rates, we first determined the number of HP tracts of a given length in unique regions of the genome which had ≥ sevenfold sequence coverage. We then used the following equation to calculate mutation rate: (number of indels)/(160 generations)/(number of HP tracts with ≥ sevenfold coverage).