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. 2011 Jun 14;27(13):i222–i229. doi: 10.1093/bioinformatics/btr227

Fig. 1.

Fig. 1.

Decision Tree example with SNPs, individual counts of two classes and the Gini impurities. The Gini gain of the split at this SNP can be calculated as (0.5−0.1*0.32−0.3*0.5−0.6*0.44)=0.004.