Table 2.

ANOVA values for tests of Licks Relative to Water values as a function of genotype and concentration for test session 1

	Glucose	Maltose	Maltotriose	Polycose
T1R2
Genotype	F(1,11) = 19.426, p = 0.001	F(1,13) = 5.882, p = 0.031	F(1,11) = 20.167, p = 0.001	F(1,19) = 2.558, p = 0.126
Concentration	F(5,55) = 8.419, p < 0.001	F(5,65) = 8.401, p < 0.001	F(5,55) = 10.634, p < 0.001	F(5,95) = 62.128, p < 0.001
Genotype × Concentration	F(5,55) = 6.538, p < 0.001	F(5,65) = 8.457, p < 0.001	F(5,55) = 8.336, p < 0.001	F(5,95) = 1.388, p = 0.236
T1R3
Genotype	F(1,14) = 8.256, p = 0.012	F(1,11) = 2.498, p = 0.142	F(1,11) = 12.802, p < 0.001	F(1,10) < 0.001, p = 0.999
Concentration	F(5,70) = 4.625, p = 0.001	F(5,55) = 27.826, p < 0.001	F(5,55) = 5.714, p < 0.001	F(5,50) = 37.605, p < 0.001
Genotype × Concentration	F(5,70) = 4.283, p = 0.002	F(5,55) = 17.220, p < 0.001	F(5,55) = 11.372, p < 0.001	F(5,50) = 0.362, p = 0.872
T1R2/3
Genotype	F(1,19) = 19.024, p < 0.001	F(1,18) = 29.711, p < 0.001	F(1,18) = 22.204, p < 0.001	F(1,21) = 7.408, p = 0.013
Concentration	F(5,95) = 3.724, p = 0.004	F(5,90) = 21.572, p < 0.001	F(5,90) = 13.342, p < 0.001	F(5,105) = 48.874, p < 0.001
Genotype × Concentration	F(5,95) = 5.938, p < 0.001	F(5,90) = 23.547, p < 0.001	F(5,90) = 11.498, p < 0.001	F(5,105) = 4.326, p = 0.001