Table 3.

ANOVA values for tests of Licks Relative to Water values as a function of genotype and concentration for test session 3

	Glucose	Maltose	Maltotriose	Polycose
T1R2
Genotype	F(1,11) = 5.124, p = 0.045	F(1,12) = 1.376, p = 0.263	F(1,9) = 0.229, p = 0.644	F(1,20) = 0.438, p = 0.516
Concentration	F(5,55) = 24.438, p < 0.001	F(5,60) = 112.836, p < 0.001	F(5,45) = 48.782, p < 0.001	F(5,100) = 178.154, p < 0.001
Genotype × Concentration	F(5,55) = 7.961, p < 0.001	F(5,60) = 8.17, p < 0.001	F(5,45) = 5.777, p < 0.001	F(5,100) = 0.621, p = 0.684
T1R3
Genotype	F(1,12) = 6.447, p = 0.026	F(1,11) = 2.634, p = 0.133	F(1,11) = 0.255, p = 0.624	F(1,9) = 5.887, p = 0.038
Concentration	F(5,60) = 27.340, p < 0.001	F(5,55) = 40.956, p < 0.001	F(5,55) = 42.739, p < 0.001	F(5,45) = 164.077, p < 0.001
Genotype × Concentration	F(5,60) = 19.035, p < 0.001	F(5,55) = 5.853, p < 0.001	F(5,55) = 3.646, p < 0.001	F(5,45) = 4.560, p = 0.002
T1R2/3
Genotype	F(1,20) = 93.644, p < 0.001	—	F(1,16) = 0.065, p = 0.802	F(1,20) = 0.253, p = 0.620
Concentration	F(5,100) 32.815, p < 0.001	—	F(5,80) = 35.590, p < 0.001	F(5,100) = 96.541, p < 0.001
Genotype × Concentration	F(5,100) = 20.909, p < 0.001	—	F(5,80) = 21.149, p < 0.001	F(5,100) = 18.050, p < 0.001