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. 2012 Jul 23;7(7):e41098. doi: 10.1371/journal.pone.0041098

Figure 1. Second-chance scenario for a bacterial flagellar motor unit.

Figure 1

The diagram shows the pathways by which traveling switch components of the rotor (circles) stimulate a motor unit (square sides). At time zero, the motor in the ground state (C) has the null probability of being excited (blue). Formation of a collision complex (Cj*; j = 1,2) stimulates a motor unit to an excited state (M) with probability (PM) of unity (red). While PM decays (color key in inset), the rotor traveling at a constant rate, k r, breaks contact with one switch complex (U1) at rate k r− = k r and delivers another switch complex (Ui, i>1) to the motor unit at rate k r+ = k r. The ligand concentration, [L], determines whether a switch can form a collision complex (filled circle; U) or not (open circle; u). If by chance, θ = K L[L]/(1+K L[L]), the switch complex at the dwell site is occupied by ligand, and the formation of Cj* restores PM to unity. An equilibrium pathway is required to initiate motor unit excitation (Eq. 1, 2, and 4; Fig. 1). The second-chance pathway (Eq. 1, 3, and 4; Fig. 1) can sustain the excited state. To emphasize the pathway-dependent free energy of the collision complex, the subscripts in C1* and C2* are included in the symbols for intermediate products of the equilibrium and second-chance pathways (Reactions 2 and 3), respectively. It should be noted that C1*, C2*, and Cj* represent the same change in physical structure of the motor unit as is represented by the transition between diamonds and squares in the schematic. To recapitulate, temporal changes in PM may be traced for the scenario shown (inset). Decay of the excited state is by single exponential (inset). In a different scenario, had the motor unit returned to the ground state before being stimulated again, the equilibrium pathway would have been required to initiate a new excited state.