Table 2.

Concentration-response analysis with ANOVA values comparing all animals that learned the discrimination task

Stimulus and Group	Genotype	Concentration	Genotype × Concentration
NaCl
T1R2	F (1,16) = 1.214, P = 0.287	F (9,144) = 82.842, P < 0.001	F (9,144) = 1.026, P = 0.423
T1R3	F (1,12) = 0.162, P = 0.695	F (9,108) = 48.000, P < 0.001	F (9,108) = 0.417, P = 0.924
Polycose 1
T1R2	F (1,14) = 2.500, P = 0.136	F (9,126) = 51.554, P < 0.001	F (9,126) = 2.613, P = 0.008
T1R3	F (1,12) = 5.499, P = 0.037	F (9,108) = 39.944, P < 0.001	F (9,108) = 3.469, P = 0.001
Polycose 2
T1R2	F (1,14) = 0.095, P = 0.762	F (6,84) = 84.084, P < 0.001	F (6,84) = 1.235, P = 0.297
T1R3	F(1,12) = 0.535, P = 0.478	F (6,72) = 2.283, P < 0.001	F (6,72) = 2.283, P = 0.045
Maltose
T1R2	F (1,12) = 7.346, P = 0.019	F (8,96) = 71.126, P < 0.001	F (8,96) = 10.931, P < 0.001
T1R3	F (1,8) = 9.510, P = 0.015	F (8,64) = 48.468, P < 0.001	F (8,64) = 11.650, P < 0.001
Glucose
T1R2	F (1,11) = 29.190, P < 0.001	F (7,77) = 55.068, P < 0.001	F (7,77) = 7.611, P < 0.001
T1R3
Sucrose 2
T1R2	F (1,10) = 92.035, P < 0.001	F (7,70) = 24.291, P < 0.001	F (7,70) = 7.371, P < 0.001
T1R3