Table 2.
Possible combinations of ethylene (C2), 1-hexene (C6), and 1-heptene (C7) dimers and trimers that make up the observed product distributionsa
Ethylene | Ethylene/1-Hexene | Ethylene/1-Hepteneb |
---|---|---|
| ||
C2 + C2 + C2 = C6 | C2 + C2 + C2 = C6 | C2 + C2 + C2 = C6 |
C2 + C2 + C6 = C10 | C2 + C2 + C6 = C10 | C2 + C2 + C6 = C10 |
C6 + C6 = C12 | C2 + C2 + C7 = C11 | |
C2 + C2 + C10 = C14 | C6 + C7 = C13 | |
C2 + C6 + C6 = C14 | C7 + C7 = C14 | |
C2 + C2 + C14 = C18 | C2 + C2 + C10 = C14 | |
C6 + C6 + C6 = C18 | C2 + C6 + C6 = C14 | |
C2 + C6 + C7 = C15 | ||
C2 + C7 + C7 = C16 |
Each combination must satisfy the following criteria: 1) homo-oligomerization of ethylene form trimers, 2) co-oligomerization of ethylene/LAO forms trimers, 3) homo-oligomerization of LAO forms dimers and trimers, 4) dimers do not form between LAO and ethylene, and 5) tetramers of alkenes do not form.
Use of 1-heptene allowed the determination of trimers formed from two molecules of LAOs and one molecule of ethylene.