Table 1.
Host |
Human (n = 369) |
Livestock (n = 45) |
||||
---|---|---|---|---|---|---|
Assemblage* | Num | Obs.% | Exp.% | Num | Obs.% | Exp.% |
000 |
140 |
38 |
6 |
11 |
34 |
2 |
001 |
4 |
1 |
10 |
0 |
0 |
5 |
010 |
1 |
0 |
10 |
0 |
0 |
5 |
011 |
6 |
2 |
15 |
0 |
0 |
14 |
100 |
0 |
0 |
9 |
0 |
0 |
5 |
101 |
0 |
0 |
14 |
0 |
0 |
14 |
110 |
1 |
0 |
14 |
0 |
0 |
14 |
111 |
217 |
59 |
22 |
34 |
64 |
43 |
Host |
Cat (n = 17) |
Dog (n = 55) |
||||
Assemblage* |
Num |
Obs.% |
Exp.% |
Num |
Obs.% |
Exp.% |
000 |
7 |
41 |
7 |
24 |
44 |
11 |
001 |
0 |
0 |
10 |
1 |
2 |
11 |
010 |
0 |
0 |
10 |
0 |
0 |
12 |
011 |
0 |
0 |
14 |
0 |
0 |
11 |
100 |
0 |
0 |
10 |
1 |
2 |
14 |
101 |
0 |
0 |
14 |
1 |
2 |
13 |
110 |
0 |
0 |
14 |
3 |
5 |
14 |
111 | 10 | 59 | 20 | 25 | 45 | 14 |
* Letter 0 is a wildcard that designates either A (human, livestock, and cat assemblages) or C (dog). Similarly, letter 1 designates one of B (human), E (livestock), D (dog), or F (cat). Expected (Exp.) frequencies were calculated by multiplying the frequencies of genotype 0 at each locus with the frequencies of genotype 1 at each locus in eight possible ways. For comparison, the frequency of observed (Obs.) is displayed as well.