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. 2012 May 3;11(9):558–570. doi: 10.1074/mcp.M112.017004

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© 2012 by The American Society for Biochemistry and Molecular Biology, Inc.

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Fig. 4. — The proportion of ¹³C and ¹²C isotopic forms of selected proteins is depicted for the wild type and the clpP mutant in the soluble and nonsoluble fraction; (exp. growth phase, transient phase (0 h), 5 h, 10 h, 15 h, and 20 h of stationary phase). The isotopic proportions of the soluble and nonsoluble fraction were calculated by normalization against the sum of all isotopic values for each protein in a fraction $(v a l u e {}^{13}C, s o lub l e f r a c t i o n_{t_{x}} = \frac{{({}^{13}C / {}^{15}N)}_{t_{x}}}{\sum_{i = 1}^{6} {({}^{13}C / {}^{15}N + {}^{12}C / {}^{15}N)}_{t_{i}}}; v a l u e {}^{12}C, s o lub l e f r a c t i o n_{t_{x}} = \frac{{({}^{12}C / {}^{15}N)}_{t_{x}}}{\sum_{i = 1}^{6} {({}^{13}C / {}^{15}N + {}^{12}C / {}^{15}N)}_{t_{i}}}; v a l u e {}^{13}C, n o n s o lub l e f r a c t i o n_{t_{x}} = - \frac{{({}^{13}C / {}^{15}N)}_{t_{x}}}{\sum_{i = 1}^{6} {({}^{13}C / {}^{15}N + {}^{12}C / {}^{15}N)}_{t_{i}}}; v a l u e {}^{12}C, n o n s o lub l e f r a c t i o n_{t_{x}} = - \frac{{({}^{12}C / {}^{15}N)}_{t_{x}}}{\sum_{i = 1}^{6} {({}^{13}C / {}^{15}N + {}^{12}C / {}^{15}N)}_{t_{i}}})$ .