Table 1. EWAS power simulation.
| (Number of cases, number of controls) |
Power (%) to detect an MVP | |||
|---|---|---|---|---|
| Scenario a |
meth OR = 1.24 md = 3.6% |
meth OR = 1.49 md = 7.2% |
meth OR = 1.78 md = 10.8% |
meth OR = 2.10 md = 14.4% |
| (100,100) | 0 0 | 0 0 | 2 0 | 18 1 |
| (200,200) | 0 0 | 4 0 | 55 11 | 99 78 |
| (400,400) | 1 0 | 66 21 | 100 98 | 100 100 |
| (800,800) | 20 3 | 100 99 | 100 100 | 100 100 |
| Scenario b |
meth OR = 1.24 md = 3.6% |
meth OR = 1.49 md = 7.2% |
meth OR = 1.78 md = 10.8% |
meth OR = 2.10 md = 14.4% |
| (100,100) | 0 0 | 1 0 | 13 1 | 60 19 |
| (200,200) | 0 0 | 16 2 | 84 46 | 100 97 |
| (400,400) | 2 0 | 85 51 | 100 100 | 100 100 |
| (800,800) | 33 8 | 100 100 | 100 100 | 100 100 |
| Scenario c |
meth OR = 1.27 md = 1.25% |
meth OR = 1.54 md = 2.5% |
meth OR = 1.82 md = 3.75% |
meth OR = 2.11 md = 5.0% |
| (100,100) | 1 0 | 37 10 | 95 77 | 100 99 |
| (200,200) | 7 1 | 95 78 | 100 100 | 100 100 |
| (400,400) | 50 19 | 100 100 | 100 100 | 100 100 |
| (800,800) | 98 88 | 100 100 | 100 100 | 100 100 |
Power (%) to detect an MVP at α = 10−6 (left entry in each cell) and α = 10−8 (right entry) for the sample sizes stated in column 1 under scenarios (a), (b) and (c) of Figure 2. methOR = methylation odds ratio, the odds for a random DNA strand in the tissue sample from a random case to be methylated, divided by the same odds for controls; md = difference in mean methylation rate between cases and controls. Analysis is via a Wald test in logistic regression implemented in the R software.