Table 4.
The usefulness of pharmacovigilance activities is to: | Total (532) no (%) | GP (169) no (%) | Non-GP (363)* no (%) |
---|---|---|---|
Measure the incidence of adverse effects; | 313 (58.83) | 94 (55.62) | 219 (60.33) |
Identify diseases for which the most commonly prescribed is a particular drug; | 75 (14.10) | 17 (10.06) | 58 (15.98) |
Identify factors that predispose to the occurrence of reactions (e.g., dose, age); | 303 (56.95) | 99 (58.58) | 204 (56.20) |
Identify new, unknown, rare, or bizarre adverse drug reactions; | 328 (61.65) | 91 (53.85) | 237 (65.29) |
Allow comparison of ADRs in the same therapeutic class; | 199 (37.41) | 56 (33.14) | 143 (39.39) |
Reduce the incidents occurring because of adverse drug reactions | 376 (70.68) | 121 (71.60) | 255 (70.25) |
Factors that might encourage voluntary reporting of adverse reactions (one or multiple choices) | Total (532) no (%) | GP (169) no (%) | non-GP (363)** no (%) |
---|---|---|---|
For each report feedback provided from NAMMD and/or marketing authorization holder; | 201 (37.78) | 69 (40.83) | 132 (36.36) |
Periodic inform physician about all adverse reactions reported and the measures taken; | 321 (60.34) | 114 (67.46) | 207 (57.02) |
Ease of reporting (e.g., online reporting); | 364 (68.42) | 110 (65.09) | 254 (69.97) |
Periodic training of medical staff on reporting utility | 256 (48.12) | 66 (39.05) | 190 (52.34) |
Monthly discussion of rare ADRs received by NMMDA. | 124 (23.31) | 37 (21.89) | 87 (23.97) |
Opinion about ADRs reporting: | Total (532) no (%) | GP (169) no (%) | non-GP (363)*** no (%) |
---|---|---|---|
Should be mandatory; | 265 (49.81) | 77 (45.56) | 188 (51.79) |
Should be voluntarily; | 168 (31.58) | 60 (35.50) | 108 (29.75) |
Should be optional and paid; | 63 (11.84) | 24 (14.20) | 39 (10.74) |
I do not know | 25 (4.70) | 6 (3.55) | 19 (5.23) |
No answer | 6 (1.13) | 1 (0.59) | 5 (1.38) |
Is useless; | 5 (0.94) | 1 (0.59) | 4 (1.10) |
x2 = 4.93; df = 5; p = 0.425;
** x2 = 7,46; df = 4; p = 0.114;
*** x2 = 4,92; df = 5; p = 0.426