Table 1.
No. of Subjects in a Poola | No. of Pools | Central-Processing-Unit Time(s) | No. of Iterations | LOD Scoreb | χ2b | P |
1 | 156 | 11.26 | 40 | 121.3 | 558.5 | 10−82 |
2 | 78 | 5.93 | 142 | 75.0 | 345.5 | 10−42 |
4 | 39 | 30.86 | 72 | 44.5 | 204.8 | 10−17 |
Genotypic data from one, two, or four subjects were mixed to make a pool.
The methods for the calculation of the LOD score and the χ2 value were as described in the “Methods” section. The degrees of freedom should be 57, as calculated by equation (3).