Table 1.

Transmission Probabilities (of Offspring Genotypes) and Penetrances (of Offspring Phenotypes), Conditioned on Indicated Parental Genotypes, for Parental Genotypes Compatible with Unaffected Mother × Unaffected Father MT^[Note]

	Transmission Probabilities When Unaffected Mother's Genotype Is
UnaffectedFather's Genotype	dd; p2	Dd; 2pq(1-f)	DD; q2(1-f)
dd; p2	dd; P(dd)=1, P(aff|dd)=0, P(unaff|dd)=1	dd; P(dd)=.5, P(aff|dd)=0, P(unaff|dd)=1
		Dd; P(Dd)=.5, P(aff|Dd)=fm, P(unaff|Dd)=1-fm	Dd; P(Dd)=1, P(aff|Dd)=fm, P(unaff|Dd)=1-fm
Dd; 2pq(1-f)	dd; P(dd)=.5, P(aff|dd)=0, P(unaff|dd)=1	dd; P(dd)=.25, P(aff|dd)=0, P(unaff|dd)=1
	Dd; P(Dd)=.5, P(aff|Dd)=fp, P(unaff|Dd)=1-fp	Dd; P(Dd)=.5, ,	Dd; P(Dd)=.5, P(aff|Dd)=fm, P(unaff|Dd)=1-fm
		DD; P(DD)=.25, P(aff|DD)=fmp, P(unaff|DD)=1-fmp	DD; P(DD)=.5, P(aff|DD)=fmp, P(unaff|DD)=1-fmp
DD; q2(1-f)	Dd; P(Dd)=1, P(aff|Dd)=fp, P(unaff|Dd)=1-fp	Dd; P(Dd)=.5, P(aff|Dd)=fp, P(unaff|Dd)=1-fp
		DD; P(DD)=.5, P(aff|DD)=fmp, P(unaff|DD)=1-fmp	DD; P(DD)=1, P(aff|DD)=fmp, P(unaff|DD)=1-fmp

Note.— We define f_mp as f_m+f_p-f_mf_p (see text).