Table 3.

Frequency counts of samples in each class for pairwise genes.

Class	xij > xil	xij < xil	Total
C 1	Pf 11	Pf 12	Pn 1 = Pf 11 + Pf 12
⋮	⋮	⋮	⋮
C m	Pf m1	Pf m2	Pn m = Pf m1 + Pf m2
Total	$P{T}_1={\displaystyle \sum }_{k=1}^{m}P{f}_{k1}$	$P{T}_2={\displaystyle \sum }_{k=1}^{m}P{f}_{k2}$	$PN={\displaystyle \sum }_{k=1}^{m}P{n}_k$