Table 1.

Proposed reactions for acetyl radical generation in tobacco smoke.

No.	Reaction	Reaction rate constantsa
1	2NO + O2 → 2NO2	k1= 2.0 × 10−38
2	CH3CHO + NO2 → CH3C(O) · +HNO2	k2= 3.36 × 10−23
3	CH3C(O) · +3AP → CH3C(O) − 3AP	k3= 5.00 × 10−12
4	CH3C(O) · +O2 → CH3C(O)O2·	k4= 5.00 × 10−12
5	CH3C(O)O2 · +NO + O2 → CH3O2 · +NO2 + CO2	k5= 2.4 × 10−11
6	CH3O2 · +NO → CH3O · +NO2	k6= 8.9 × 10−12
7	CH3O · +O2 → HCHO + HO2·	k7= 1.65 × 10−15
8	HO2 · +NO → NO2 + OH·	k8= 8.91 × 10−12
9	CH3CHO + OH · → CH3C(O) · +H2O	k9= 1.50 × 10−11
10	NO2 + C5H8 → R·	k10b = 1.81 × 10−19
11	R· +O2 → RO2·	k11= 5.00 × 10−12
12	RO2 · +NO → RO · +NO2	k12= 8.9 × 10−12
13	RO · +O2 → R′CHO + HO2·	k13= 1.9 × 10−15
14	C5H8 + OH · → R·	k14c= 1.01 × 10−15

^aUnits for second order rate constants: cm³/molecule s;

Third order third rate constants: cm⁶/molecule² s; all rate constants for 298 K. (Atkinson et al., 2004; Atkinson et al., 1997; Atkinson, et al., 2006; Jaffe and Wan, 1974; Orlando et al., 2003; Pandis, 1998; Paulson et al., 1992)

^b,cR= C₅H₈-NO₂ or C₅H₈-OH