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. Author manuscript; available in PMC: 2015 Jan 21.
Published in final edited form as: J Speech Lang Hear Res. 2011 Dec 23;55(1):55–69. doi: 10.1044/1092-4388(2011/09-0257)
Growth ModelDVAR (i.e., ΔDVAR)
 Level 1 Model
  DVARijk = Π0jk + Π1jk (G2ijk) + Π2jk (TIMEMG1Gijk) + Π3jk (G2 × TIMEijk) + eijk
 Level 2 Model
  Π0jk = θ0 + b00j + c00k
  Π1jk = θ1
  Π2jk = θ2 + b20j
  Π3jk = θ3
Growth ModelLetter-Word Identification
 Level 1 Model
  LWIDit = Π0 + Π1 (Grade 1 Month) + Π2 (Grade 2) + Π3 (Grade 2 Month) + ε
 Level 2 Model
  Π0 = β00 + β01 (DVAR) + r0
  Π1 = β10 + β11 (DVAR) + r1
  Π2 = β20 + β21 (DVAR) + r2
  Π3 = β30 + β31 (DVAR) + r3
Growth ModelPassage Comprehension
 Level 1 Model
  PCit = Π0 + Π1 (Grade 1 Month) + Π2 (Grade 2) + Π3 (Grade 2 Month) + ε
 Level 2 Model
  Π0 = β00 + β01 (DVAR)
  Π1 = β10 + β11 (DVAR) + r1
  Π2 = β20 + β21 (DVAR)
  Π3 = β30 + β31 (DVAR) + r3
 Model fitting: A series of sequential models were initially tested to examine which model best fit the data: (a) fixed intercept–fixed slope, (b) random intercept–fixed slope, (c) fixed intercept–random slope, and (d) random intercept–random slope. Following this test, the better fitting model was examined for variability in intercepts and slopes. Results from the −2 log likelihood test suggest that the random intercept–random slope model improved the description of growth for letter–word identification, χ2(7) = 40.22, p < .001, whereas the fixed intercept-random slope model was a better descriptor for growth in reading, χ2(7) = 80.45, p < .001. We then entered ΔDVAR into the model at Level 2. Nonsignificant variance components were fixed to achieve greater power in model estimation.
Proportion Reduction in Variance
τqq(UC)-τqq(C)τqq(UC),
where τ̑qq (UC) represents the tau estimate for a given parameter (e.g., intercept) for the unconditional model and τ̑qq (C) is a tau estimate for the conditional model (Raudenbush & Bryk, 2002).