Table 3.

Voltage dependence of ionic channels in the simplified model neuron.

$C_m\frac{dV}{dt}=-(I_{\mathit{\text{Ca}}}+I_{Kd}+I_{MI}+I_{\mathit{\text{leak}}})$
$I_{\mathit{\text{Ca}}}={Ḡ}_{\mathit{\text{Ca}}}{m}_{\infty \mathit{\text{Ca}}}^3{h}_{\infty \mathit{\text{Ca}}}(V-E_{\mathit{\text{Ca}}})$	$I_{Kd}={Ḡ}_{Kd}{m}_{Kd}^4(V-E_K)$
$m_{\infty \mathit{\text{Ca}}}=\frac{1}{1+{\mathrm{e}}^{0.185(-60.6-\mathrm{V})}},h_{\infty \mathit{\text{Ca}}}=\frac{1}{1+{\mathrm{e}}^{-0.15(-65-\mathrm{V})}}$ ECa = +128 mV	${\tau }_{mKd}\frac{d{m}_{Kd}}{dt}=m_{\infty Kd}-m_{Kd}$
	$m_{\infty Kd}=\frac{1}{1+{\mathrm{e}}^{0.05(-35-\mathrm{V})}}$
	τmKd = 400 msec, ḠKd = 10.2 µS, EK = −80 mV
IMI = ḠMIm∞MI(V−EMI)	ILeak = Gleak(V−Eleak)
$m_{\infty MI}=\frac{1}{1+{\mathrm{e}}^{0.2(-55-\mathrm{V})}}$	Gleak = 0.03 µS, Eleak = −68 mV
ḠMI = 0.02 µS, EMI = −10 mV	Cm = 0.2 nF