Table 1.

The statistical output, F ratios and p values obtained from the analysis of TWA parameters using one-way repeated measures ANOVA.

		Avoidances	Escapes	Failures	Avoidance latency	Escape latency
Effect of training	10 mg/kg	F(2.79,108.80) = 44.75,	F(2.77,108.06) = 43.17,	F(2.69,105.13) = 3.26,	F(2.88,95.22) = 4.22,	F(2.9,114.51) = 23.31,
		p < 0.001	p < 0.001	p < 0.05	p < 0.005	p < 0.001
	5 mg/kg	F(2.83,51.02) = 21.54,	F(2.96,53.39) = 23.95,	F(2.58,46.55) = 1.05,	F(4,72) = 6.32,	F(2.27,40.88) = 5.09,
		p < 0.001	p < 0.001	p = 0.372	p < 0.001	p < 0.005
	1 mg/kg	F(4,72) = 47.58,	F(2.58,46.56) = 14.49,	F(2.21,39.88) = 5.65,	F(2.18,39.26) = 2.24,	F(2.27,40.91) = 10.76,
		p < 0.001	p < 0.001	p < 0.01	p = 0.115	p < 0.001
Interaction effect of drug treatment and training	10 mg/kg	F(2.79,108.80) = 0.37,	F(2.77,108.06) = 0.44,	F(2.69,105.13) = 1.13,	F(2.88,95.22) = 0.10,	F(2.9,114.51) = 0.20,
		p = 0.758	p = 0.707	p = 0.337	p = 0.955	p < 0.8
	5 mg/kg	F(2.83,51.02) = 0.68,	F(2.96,53.39) = 1.28,	F(2.58,46.55) = 0.57,	F(4,72) = 1.26,	F(2.27,40.88) = 0.70,
		p = 0.558	p = 0.284	p = 0.609	p = 0.293	p = 0.523
	1 mg/kg	F(4,72) = 1.54,	F(2.58,46.56) = 0.49,	F(2.21,39.88) = 1.06,	F(2.18,39.26) = 0.22,	F(2.27,40.91) = 1.66,
		p = 0.199	p = 0.660	p = 0.361	p = 0.816	p = 0.199
Comparison between vehicle and MO groups	10 mg/kg	F(1,39) = 12.85,	F(1,39) = 10.50,	F(1,39) = 8.75,	F(1,33) = 0.12,	F(1,39) = 4.60,
		p = 0.345	p = 0.296	p = 0.894	p = 0.797	p = 0.429
	5 mg/kg	F(1,18) = 0.93,	F(1,18) = 1.15,	F(1,18) = 0.02,	F(1,18) = 0.07,	F(1,18) = 0.66,
		p = 0.345	p = 0.296	p = 0.894	p = 0.797	p = 0.429
	1 mg/kg	F(1,18) = 0.48,	F(1,18) = 1.95,	F(1,18) = 0.99,	F(1,18) = 0.38,	F(1,18) = 0.96,
		p = 0.497	p = 0.179	p = 0.334	p = 0.546	p = 0.340