Figure 3a (For electron x)

Figure 3a (For electron y)

$U_1=\frac{A}{r_1}=\frac{23.04\times {10}^{-29}}{20\times {10}^{-9}}\approx 1.15\times {10}^{-20}J$ $U_2=\frac{A}{r_2}=\frac{23.04\times {10}^{-29}}{18.11\times {10}^{-9}}\approx 1.27\times {10}^{-20}J$ $U_3=\frac{A}{r_3}=\frac{23.04\times {10}^{-29}}{2\times {10}^{-9}}\approx 11.52\times {10}^{-20}J$ $U_4=\frac{A}{r_4}=\frac{23.04\times {10}^{-29}}{26.91\times {10}^{-9}}\approx 0.86\times {10}^{-20}J$ $U_5=\frac{A}{r_5}=\frac{23.04\times {10}^{-29}}{20\times {10}^{-9}}\approx 1.15\times {10}^{-20}J$ $U_6=\frac{A}{r_6}=\frac{23.04\times {10}^{-29}}{42.04\times {10}^{-9}}\approx 0.55\times {10}^{-20}J$ $U_7=\frac{A}{r_7}=\frac{23.04\times {10}^{-29}}{44.72\times {10}^{-9}}\approx 0.52\times {10}^{-20}J$ $U_8=\frac{A}{r_8}=\frac{23.04\times {10}^{-29}}{43.91\times {10}^{-9}}\approx 0.53\times {10}^{-20}J$ $U_9=\frac{A}{r_9}=\frac{23.04\times {10}^{-29}}{44.72\times {10}^{-9}}\approx 0.52\times {10}^{-20}J$ $U_{10}=\frac{A}{r_{10}}=\frac{23.04\times {10}^{-29}}{69.34\times {10}^{-9}}\approx 0.33\times {10}^{-20}J$ $U_{T_{}{x}_1}^{-}={\sum }_{i=1}^{10}{U}_i=18.38\times {10}^{-20}J$

$U_1=\frac{A}{r_1}=\frac{23.04\times {10}^{-29}}{42.04\times {10}^{-9}}\approx 0.55\times {10}^{-20}J$ $U_2=\frac{A}{r_2}=\frac{23.04\times {10}^{-29}}{20\times {10}^{-9}}\approx 1.15\times {10}^{-20}J$ $U_3=\frac{A}{r_3}=\frac{23.04\times {10}^{-29}}{26.91\times {10}^{-9}}\approx 0.86\times {10}^{-20}J$ $U_4=\frac{A}{r_4}=\frac{23.04\times {10}^{-29}}{38\times {10}^{-9}}\approx 0.61\times {10}^{-20}J$ $U_5=\frac{A}{r_5}=\frac{23.04\times {10}^{-29}}{18.11\times {10}^{-9}}\approx 1.27\times {10}^{-20}J$ $U_6=\frac{A}{r_6}=\frac{23.04\times {10}^{-29}}{20\times {10}^{-9}}\approx 1.15\times {10}^{-20}J$ $U_7=\frac{A}{r_7}=\frac{23.04\times {10}^{-29}}{58.03\times {10}^{-9}}\approx 0.40\times {10}^{-20}J$ $U_8=\frac{A}{r_8}=\frac{23.04\times {10}^{-29}}{44.72\times {10}^{-9}}\approx 0.52\times {10}^{-20}J$ $U_9=\frac{A}{r_9}=\frac{23.04\times {10}^{-29}}{22.09\times {10}^{-9}}\approx 1.04\times {10}^{-20}J$ $U_{10}=\frac{A}{r_{10}}=\frac{23.04\times {10}^{-29}}{44.72\times {10}^{-9}}\approx 0.52\times {10}^{-20}J$ $U_{T_{y_1}}^{-}={\sum }_{i=1}^{10}{U}_i=8.05\times {10}^{-20}J$