Table I.
Description of simulation scenarios. k: total number of traits, k1: number of associated traits. In tables X-XIII, since the third and the fourth traits are not associated with the QTL, we impose (a3, b3) = (a4, b4) = (0, 0) in each of choices 1-4.
trait-specific QTL effects and
heritabilities | |||||
---|---|---|---|---|---|
Tables | (k, k1) | choice 1 | choice2 | choice 3 | choice 4 |
X | (4,2) | a1=1.0, b1=0.0 | a1=1.0, b1=0.0 | a1=1.0, b1=0.0 | a1=1.0, b1=0.0 |
a2=1.0, b2=0.0 | a2=2.0, b2=0.0 | a2=1.0, b2=0.5 | a2=–1.0, b2=0.0 | ||
XI | (4,2) | same as Table X | same as Table X | same as Table X | same as Table X |
XII | (4,2) | In Table X, first | continuous trait | is converted to | a binary trait |
XIII | (4,2) | In Table XI, first | continuous trait | is converted to | a binary trait |
XIV | (4,4) | a1=1.0, b1=0.0 | a1=1.0, b1=0.0 | a1=1.0, b1=0.0 | a1=1.0, b1=0.0 |
a2=1.0, b2=0.0 | a2=2.0, b2=0.0 | a2=1.0, b2=0.5 | a2=–1.0, b2=0.0 | ||
a3=1.0, b3=0.0 | a3=1.0, b3=0.0 | a3=1.0, b3=0.0 | a3=1.0, b3=0.0 | ||
a4=1.0, b4=0.0 | a4=2.0, b4=0.0 | a4=1.0, b4=0.5 | a4=–1.0, b4=0.0 | ||