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. 2016 Aug 17;17:647. doi: 10.1186/s12864-016-2991-9

Table 1.

An example showing how Bray-Curtis dissimilarity was calculated between strain I and strain J. (Note: dissimilarity calculation in real case would be more complex because typical microbial genomes usually comprise thousands of genes)

Orthologous groups # genes mapped in strain I # genes mapped in strain J C n * C ij # S i $ S j % BC ij&
OG1 1 1 1 7 9 11 0.3
OG2 2 4 2
OG3 4 2 2
OG4 0 2 0
OG5 2 2 2

* C n was the number of common genes assigned to the same orthologous group, the lesser number of mapped genes was used

# C ij was the sum of C n, and represented the total number of genes assigned to common orthologous groups between strain I and J

$ S i was the total number of genes in strain I mapped to orthologous groups in eggNOG database

% S j was the total number of genes in strain J mapped to orthologous groups in eggNOG database

& BC ij is the Bray-Curtis dissimilarity between strain I and J