Table 1.
An example showing how Bray-Curtis dissimilarity was calculated between strain I and strain J. (Note: dissimilarity calculation in real case would be more complex because typical microbial genomes usually comprise thousands of genes)
Orthologous groups | # genes mapped in strain I | # genes mapped in strain J | C n * | C ij # | S i $ | S j % | BC ij& |
---|---|---|---|---|---|---|---|
OG1 | 1 | 1 | 1 | 7 | 9 | 11 | 0.3 |
OG2 | 2 | 4 | 2 | ||||
OG3 | 4 | 2 | 2 | ||||
OG4 | 0 | 2 | 0 | ||||
OG5 | 2 | 2 | 2 |
* C n was the number of common genes assigned to the same orthologous group, the lesser number of mapped genes was used
# C ij was the sum of C n, and represented the total number of genes assigned to common orthologous groups between strain I and J
$ S i was the total number of genes in strain I mapped to orthologous groups in eggNOG database
% S j was the total number of genes in strain J mapped to orthologous groups in eggNOG database
& BC ij is the Bray-Curtis dissimilarity between strain I and J