Fig. 4.

Reorganization of the nuclear architecture. The figures in the second row are displayed without the heterochromatin shown in the figures displayed in the first row, in order to show the details of chromosomal rearrangements. The nucleus decreases to 60 % of its original size and acquires a circular shape. ${\mathit{\alpha }}_0=25/6,{\mathit{\alpha }}_V=10/6,{\mathit{\alpha }}_v=20/3,{\mathit{\beta }}_0=5/3,{\mathit{\beta }}_{\mathit{\varphi }}=1,{\mathit{\beta }}_{\mathit{\psi }}=2/3,\mathit{\gamma }=0.0,{\mathit{\epsilon }}_{\mathit{\varphi }}^2=0.0002,$ and ${\mathit{\epsilon }}_{\mathit{\psi }}^2=0.0006$. For ${\mathit{\rho }}_m(t)$, ${\mathit{\alpha }}_1=120,{\mathit{\alpha }}_2=0.03,T=120$ for ${\mathit{\varphi }}_1\cdots {\mathit{\varphi }}_6$ and ${\mathit{\alpha }}_1=150,{\mathit{\alpha }}_2=0.03,T=150$ for ${\mathit{\varphi }}_7,{\mathit{\varphi }}_8$. $({\overline{\mathit{\rho }}}_1,{\overline{\mathit{\rho }}}_2,{\overline{\mathit{\rho }}}_3,{\overline{\mathit{\rho }}}_4,{\overline{\mathit{\rho }}}_5,{\overline{\mathit{\rho }}}_6,{\overline{\mathit{\rho }}}_7,{\overline{\mathit{\rho }}}_8)=(0.35,0.4,0.4,0.35,0.15,0.15,0.35,0.35)$