TABLE I.

The spherical harmonic Thole damping factors for the energies (λ₀ and λ_1c/1s) and forces (λ₀′ and λ_1c/1s′) calculation in the QI frames.

l = 0	λ0	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2\right)e^{-au}$
Charge	λ0′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{4}{a}^3{u}^3\right)e^{-au}$
l = 1	λ0	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{4}{a}^3{u}^3\right)e^{-au}$
Dipole	λ1c/1s	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2\right)e^{-au}$
	λ0′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{12}{a}^4{u}^4\right)e^{-au}$
	λ1c/1s′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3\right)e^{-au}$
l = 2	λ0	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{18}{a}^4{u}^4\right)e^{-au}$
Quadrupole	λ1c/1s	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3\right)e^{-au}$
	λ0′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{24}{a}^4{u}^4{u}^3+\frac{1}{72}{a}^5{u}^5\right)e^{-au}$
	λ1c/1s′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{24}{a}^4{u}^4\right)e^{-au}$
l = 3	λ0	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{24}{a}^4{u}^4{u}^3+\frac{1}{120}{a}^5{u}^5\right)e^{-au}$
Octopole	λ1c/1s	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{30}{a}^4{u}^4\right)e^{-au}$
	λ0′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{24}{a}^4{u}^4+\frac{1}{120}{a}^5{u}^5+\frac{1}{600}{a}^6{u}^6\right)e^{-au}$
	λ1c/1s′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{1}{25}{a}^4{u}^4+\frac{1}{150}{a}^5{u}^5\right)e^{-au}$
l = 4	λ0	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{43}{1050}{a}^4{u}^4+\frac{4}{525}{a}^5{u}^5+\frac{1}{1050}{a}^6{u}^6\right)e^{-au}$
Hexadecapole	λ1c/1s	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{4}{105}{a}^4{u}^4+\frac{1}{210}{a}^5{u}^5\right)e^{-au}$
	λ0′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{29a^4{u}^4}{700}+\frac{17a^5{u}^5}{2100}+\frac{2a^6{u}^6}{1575}+\frac{a^7{u}^7}{6300}\right)e^{-au}$
	λ1c/1s′	$1-\left(1+au+\frac{1}{2}{a}^2{u}^2+\frac{1}{6}{a}^3{u}^3+\frac{17}{420}{a}^4{u}^4+\frac{1}{140}{a}^5{u}^5+\frac{1}{1260}{a}^6{u}^6\right)e^{-au}$