Algorithm 1 Binary searching algorithm to find ${\eta }^{*}$

Intput:    Parameters of detector at SU-Tx: ${\alpha }_l$, ${\alpha }_i$, N;    Parameters of detector at SU-Rx: $\rho$, N, $T_c$, $T_d$;    The upper bound on the missed detection rate: ${\beta }_0$. Output:    The optimal exponent assigned to the SU-Tx for sensitivity relaxation: ${\eta }^{*}$. 1: if $q_{tx}\left({\beta }_0\right)$ = $q_{rx}\left({\beta }_0\right)$ then 2:     ${\eta }^{*}$ = 0.5 3: else if $q_{tx}\left({\beta }_0\right)$ < $q_{rx}\left({\beta }_0\right)$ then 4:     ${\eta }_s$ = 0.5, ${\eta }_e$ = 1 5: else 6:     ${\eta }_s$ = 0, ${\eta }_e$ = 0.5 7: end if 8: while $|P_{fa}^{{}^{\prime }}\left({\eta }_s\right)-P_{fa}^{{}^{\prime }}\left({\eta }_e\right)|>ϵ$ do 9:     ${\eta }_i=({\eta }_s+{\eta }_e)/2$ 10:    if $P_{fa}^{{}^{\prime }}\left({\eta }_i\right)$ has the same sign with $P_{fa}^{{}^{\prime }}\left({\eta }_s\right)$ then 11:           ${\eta }_s={\eta }_i$ 12:     else 13:           ${\eta }_e={\eta }_i$ 14:     end if 15: end while 16: ${\eta }^{*}=({\eta }_s+{\eta }_e)/2$