Table 6.
Genotype | E I + II (%) | E III + IV (%) | E III + IV vs E I + II | ||||||
---|---|---|---|---|---|---|---|---|---|
P | OR | 95% CI | Test for independence | Test for trend | |||||
p | χ2 | p | χ2 | ||||||
LILRB1 rs41308748:G>A | N = 16 | N = 183 | |||||||
GG* | 13 (81.25) | 150 (81.97) | 1 | 0.43 | 1.70 | 0.68 | 0.17 | ||
GA | 3 (18.75) | 21 (11.48) | 0.44 | 0.61 | (0.16–2.31) | ||||
AA | 0 (0.00) | 12 (6.55) | 0.60 | 2.24 | (0.13–40.02) | ||||
Minor allele A | 3 (9.38) | 45 (12.30) | |||||||
LILRB1 rs1061680:T>C | N = 16 | N = 183 | |||||||
TT* | 12 (75.00) | 122 (66.67) | 1 | 0.63 | 0.93 | 0.38 | 0.76 | ||
TC | 4 (25.00) | 53 (28.96) | 0.78 | 1.30 | (0.40–4.23) | ||||
CC | 0 (0.00) | 8 (4.37) | 1.00 | 1.74 | (0.09–31.90) | ||||
Minor allele C | 4 (12.5) | 69 (18.85) | |||||||
LILRB2 rs383369:G>A | N = 16 | N = 183 | |||||||
AA* | 15 (93.75) | 124 (67.76) | 1 | 0.06 | 5.49 | 0.024 | 5.10 | ||
AG | 1 (6.25) | 58 (31.69) | 0.043 a | 7.02 | (0.90–54.43) | ||||
GG | 0 (0.00) | 1 (0.55) | 1.00 | 0.37 | (0.01–9.58) | ||||
Minor allele G | 1 (3.13) | 60 (16.39) | |||||||
LILRB2 rs7247538:C>T | N = 16 | N = 183 | |||||||
TT* | 6 (37.50) | 64 (34.97) | 1 | 0.51 | 1.34 | 0.69 | 0.16 | ||
CT | 6 (37.50) | 91 (49.73) | 0.56 | 1.42 | (0.44–4.61) | ||||
CC | 4 (25.00) | 28 (15.30) | 0.72 | 0.66 | (0.17–2.51) | ||||
Minor allele C | 14 (43.75) | 147 (40.16) | |||||||
KIR2DL4 rs649216:T>C | N = 16 | N = 187 | |||||||
TT* | 6 (37.50) | 60 (32.09) | 1 | 0.23 | 2.95 | 0.62 | 0.25 | ||
CT | 4 (25.00) | 85 (45.45) | 0.33 | 2.13 | (0.57–7.86) | ||||
CC | 6 (37.50) | 42 (22.46) | 0.56 | 0.70 | (0.21–2.32) | ||||
Minor allele C | 16 (50.00) | 169 (45.19) |
P probability, OR odds ratio, 95% CI 95% confidence interval from two-sided Fisher’s exact test, χ 2 df = 2 p Chi-square test for independence with two degrees of freedom for all tested polymorphisms, χ 2 df = 1 p Chi-square test for trend with one degree of freedom for all tested polymorphisms; *Reference; for four samples from the III + IV endometriosis group we could not perform LILRB1 and LILRB2 genotyping because of a lack of DNA
a P corr. = 0.215