Table B2.
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Subject | a | b | c | ||||
1 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
2 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
3 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
4 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
5 | 1 | 0 | 0 | 0.4 | 0.4 | 1 | 0.9335 |
6 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
7 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
8 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
9 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
10 | 1 | 0 | 0.4167 | 0 | 0.4167 | 1 | 0.9253 |
11 | 1 | 0.1833 | 0 | 0 | 0.1833 | 1 | 1.0406 |
12 | 0 | 0 | 0.2083 | 0.2 | 0.4083 | –0.3616 | –0.4322 |
13 | 1 | 0 | 0.4167 | 0 | 0.4167 | 1 | 0.9253 |
14 | 1 | 0 | 0 | 0.4 | 0.4 | 1 | 0.9335 |
15 | 0 | 0.0917 | 0 | 0.2 | 0.2917 | –0.3616 | –0.3745 |
Average | 0.867 | 0.266 | 0.818 | 0.818 |
This is obtained by summing columns 3, 4, and 5. bThis is computed as (i.e., Col 7 = (Col2 − 0.266)/(1 − 0.266)). cThis is computed based on Equation (16): Col8 = Col7 − 2×(1 − 0.818)×(Col6 − 0.266)/(1 − 0.266)