Table 3.
Concordance in the 92 cervical and breast samples in which one of the assays detected one or two of the 12 human papillomavirus (HPV) genotypes detected.
| SPF10LiPA25
(%a) |
Semi-Q- PCR (%a) |
Kappa-value (95% CI) |
Mc Nemar’s p-value |
|
|---|---|---|---|---|
| CIN3+ samples | ||||
| HPV 16 | 42 (45.65) | 41 (44.57) | 0.98 (0.94–1.02) | 1 |
| HPV 18 | 6 (6.52) | 7 (7.61) | 0.92 (0.76–1.08) | 1 |
| HPV 31 | 11 (11.96) | 11 (11.96) | 1 | NAc |
| HPV 33 | 8 (8.70) | 8 (8.70) | 1 | NAc |
| HPV 35 | 1 (1.09) | 1 (1.09) | – | – |
| HPV 39 | 1 (1.09) | 1 (1.09) | – | – |
| HPV 45 | 10 (10.87) | 10 (10.87) | 1 | NA |
| HPV 51 | 1 (1.09) | 1 (1.09) | – | – |
| HPV 52 | 5 (5.43) | 5 (5.43) | 1 | NA |
| HPV 56 | 2 (2.17) | 2 (2.17) | 1 | NA |
| HPV 58 | 4 (4.35) | 4 (4.35) | 1 | NA |
| HPV 59 | 1 (1.09) | 1 (1.09) | – | – |
| Total | 92b | 92b | ||
| Breast cancer samples | ||||
| HPV 16 | 2 (66.67) | 1 (100.00) | – | – |
| HPV 56 | 1 (33.33) | 0 (0.00) | – | – |
aGenotype-specific HPV prevalence: number of samples positive for a given genotype (with or without co-infection with other genotypes) divided by the number of all samples (92).
bSince some samples are positive for two HPV genotypes, the total number of HPV-positive CIN3+ samples (92) is higher than the number of CIN3+ samples tested positive for HPV (88), see Table 4.
cComplete agreement.
–,Too few positive samples, testing not appropriate.