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. Author manuscript; available in PMC: 2018 Aug 3.
Published in final edited form as: J Am Stat Assoc. 2017 Feb 28;113(522):780–788. doi: 10.1080/01621459.2017.1285777
1nlnj=lnn1Rem^njσ^njγ1/2δ5/2nlnj=lnn1(Knj)20
(Lemmas A.7, A.8, and A.9)
=γ1/2δ5/2nlnlogmax{n,p}j=lnn1j1
(Eq. A.5)
γ1/2δ5/2nlnlogmax{n.p}lognln
(abj1a1bj1dj)
=o([nln]1/2).
(Eqs. A.7 and A.8)