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. 2018 Aug 29;8:13050. doi: 10.1038/s41598-018-31412-7

Figure 1.

Figure 1

Neuronal dynamics. (A) The phase diagram. The regions of different types of solutions for the neuronal dynamics are depicted in the (quarter of the) plane of (non-negative) J21 and J12. (B). The limit cycle solution. The firing rate of populations 1 and 2 are plotted in black and blue, respectively, as a function of time (measured in units of τa) in the anti-phase oscillatory solution with T1 = 1.2 and T2 = 0.8, yielding J21 ≈ 2.36 and J12 ≈ 1.87 (see Eq. (43)). In this specific example we used I = 2, A = 2, the solid lines show the solution for ϵ=0.01 and the dashed depict the solution in the limit of ϵ0. (C) The oscillation period along the diagonal. The oscillation period on the diagonal is shown as a function of the reciprocal inhibition strength for different values of the adaptation strength, A = 0.25, 0.5, 1, 1.5 from left to right. Solid lines show the analytical relation of Eq. (44) in the ϵ0 limit. The circles depict the ϵ=0.01 case. (D) The cross-correlation function. The neuronal cross-correlations Γ12 (green and black) and Γ21 (blue) are plotted as a function of the time difference, Δ (measured in units of the adaptation time constant τa). The black line depicts the correlations in the ϵ0 limit, whereas the green and blue lines show the ϵ=0.01 case. Parameters were identical to B. For the ϵ=0.01 case the correlations were evaluated from the numerical solution for the dynamics. (E) The ‘mean cross-correlation’ function. The mean correlation, Γ+, in the limit of ϵ0, (see subsection Calculation of the cross-correlation function in Methods) is plotted as a function of Δ for T = 2 and different values of the T1 = T[0.1, 0.2, … 0.9] shown by color. Note that the plots for T1 = x and T1 = T − x overlap. (F) The ‘difference cross-correlation’. The difference in the cross-correlation, Γ, in the limit of ϵ0, is plotted as a function of Δ for T = 2 and different values of the T1 = T × {0.1, 0.2, … 0.9} shown by color from yellow (T1 = 0.1T) to blue (T1 = 0.9T). In E and F A = 2 and I = 2 were used.