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. Author manuscript; available in PMC: 2020 Apr 1.
Published in final edited form as: IEEE Trans Vis Comput Graph. 2018 Mar 27;25(4):1760–1773. doi: 10.1109/TVCG.2018.2818701

Fig. 4.

Fig. 4.

Simplification of 3D volumetric template matching to a 2D integral with a 1D template. (a) The entire template is shown, with the coordinates (ux,uy,uz) given in a consistent template space. Cross-sections of the template are shown along the y(b) and x(c) axes. Note that the template at ux=0anduy=0 are identical (d), while the template function itself can be expressed as a 1D function of distance from (ux,uy)=(0,0).