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. 2019 Mar 14;19:14. doi: 10.1186/s12898-019-0230-3

Table 2.

Statistics for the effects of sampling date, body length (mm) and their interaction on disease parameters

A. Likelihood of infection (Fig. 2c) Estimate Standard error T value Pr (> |t|)
Constant − 1.843 0.449 − 4.106 4.5×10−5
Sampling date (28 June 2015) 0.432 0.799 0.541 0.589
Body length 0.592 0.176 3.364 0.00081
Sampling date : body length 0.886 0.351 2.521 0.012
B. Time taken to show infection (Fig. 3) Estimate Standard error T value Pr (> |t|)
Constant 21.491 1.816 11.834 <2×10−16
Sampling date (28 June 2015) 7.830 2.046 3.827 0.00015
Body length − 4.098 0.690 − 5.937 5.6×10−9
Sampling date : body length − 4.318 0.775 − 5.572 4.2×10−8
C. Total number of offspring produced prior to castration (Fig. 4a) Estimate Standard error Z value Pr (> |z|)
Constant 2.013 1.908 1.055 0.291
Sampling date (28 June 2015) 3.431 2.284 1.502 0.133
Body length − 0.158 0.735 − 0.215 0.829
Sampling date : body length − 2.428 0.932 − 2.605 0.0092
D. Probability of producing a clutch prior to castration (Fig. 4b) Estimate Standard error T value Pr (> |t|)
Constant 5.618 1.273 4.412 1.4×10−5
Sampling date (28 June 2015) − 0.358 2.177 − 0.164 0.869
Body length − 1.434 0.463 − 3.098 0.0021
Sampling date : body length − 2.412 1.095 − 2.202 0.0283

A. Quasibinomial regression model fitted to analyse the likelihood of infection (0/1) (null deviance = 904.88, df = 715, residual deviance = 674.57, df = 712). B. General linear model (GLM) for the time (in days) taken to show infection (R-squared = 0.58, F3,478 = 220.1, p-value ≤ 2×10−16). C. Negative binomial generalised model for total number of offspring produced prior to parasitic castration (null deviance = 126.012, df = 226, residual deviance = 96.052, df = 223). D. Logistic regression model with quasibinomial distribution for the probability of producing at least one clutch prior to parasitic castration (null deviance = 456.58, df = 332, residual deviance = 170.43, df = 329). P-values in italic are statistically significant at the level α = 0.05