Table 3.

Magic formulas for the octahedron

	fcc octahedron n=6
	Atoms	$\frac{2}{3}{n}^3+2n^2+\frac{7}{3}n+1,n\ge 1$
	Bonds	4n3+6n2+2n, n≥0
	cn=4	6, n≥1
	cn=7	12n−12, n≥1
	cn=9	4n2−12n+8, n≥1
	cn=12	$\frac{2}{3}{n}^3-2n^2+\frac{7}{3}n-1,n\ge 1$