Table 7.

Magic formulas for the bcc octahedron

	bcc octahedron n=4
	Atoms	$\frac{8}{3}{n}^3+6n^2+\frac{16}{3}n+1,n\ge 1$
	Bonds	$\frac{56}{3}{n}^3+18n^2+\frac{40}{3}n,n\ge 0$
	cn=5	6, n≥1
	cn=7	4n2+4n, n≥0
	cn=8	12n−12, n≥1
	cn=10	4n2−12n+8, n≥1
	cn=13	4n2−4n, n≥1
	cn=14	$\frac{8}{3}{n}^3-6n^2+\frac{16}{3}n-1,n\ge 1$