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. 2019 Jul 16;19(14):3131. doi: 10.3390/s19143131
Pd2+ + 2e→Pd φ = 0.915 V.
Pd(OH)2 + 2e→Pd + 2OH φ = 0.07 V
[PdCl4]2− + 2e→Pd+ 4Cl φ = 0.621 V