Table 1.

Displacement reconstruction algorithm.

Function 1: Calculate the Dynamic Displacement of the Bridge
Input: Acceleration Signal $\mathit{a}\mathbf{\left(}\mathit{t}\mathbf{\right)}$ Output: Displacement Signal $\mathit{x}\mathbf{\left(}\mathit{t}\mathbf{\right)}$
1: for $i=1;i\le N;i++$ do	15:     if $c_j$ is an effective IMF then
2:    $A_i\left(t\right)=a\left(t\right)+n_i\left(t\right)$	16:       $v_1\left(t\right)=v_1\left(t\right)+c_j$
3:    $A_i\left(t\right)={\displaystyle {\sum }_{j=1}^K{c}_{ij}\left(t\right)+r_{iK}\left(t\right)}$	17:     end if
4: for $j=1;j\le K;j++$ do	18:$s\left(t\right)={\displaystyle {\int }_0^t{v}_1\left(t\right)}dt$
5:     $c_j=\frac{1}{N}{\displaystyle {\sum }_{i=1}^N{c}_{ij}\left(t\right)}$	19: for $i=1;i\le N;i++$ do
6:     if $c_j$ is an effective IMF then	20:    $S_i\left(t\right)=s\left(t\right)+n_i\left(t\right)$
7:       $a_1\left(t\right)=a_1\left(t\right)+c_j$	21:    $S_i\left(t\right)={\displaystyle {\sum }_{j=1}^K{c}_{ij}\left(t\right)+r_{iK}\left(t\right)}$
8:     end if	22: for $j=1;j\le K;j++$ do
9:$v\left(t\right)={\displaystyle {\int }_0^t{a}_1\left(t\right)}dt$	23:     $c_j=\frac{1}{N}{\displaystyle {\sum }_{i=1}^N{c}_{ij}\left(t\right)}$
10: for $i=1;i\le N;i++$ do	24:     if $c_j$ is an effective IMF then
11:   $V_i\left(t\right)=v\left(t\right)+n_i\left(t\right)$	25:        $s_1\left(t\right)=s_1\left(t\right)+c_j$
12:  $V_i\left(t\right)={\displaystyle {\sum }_{j=1}^K{c}_{ij}\left(t\right)+r_{iK}\left(t\right)}$	26:     end if
13: for $j=1;j\le K;j++$ do	27:$x\left(t\right)=s_1\left(t\right)$
14:    $c_j=\frac{1}{N}{\displaystyle {\sum }_{i=1}^N{c}_{ij}\left(t\right)}$