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. Author manuscript; available in PMC: 2020 Sep 1.
Published in final edited form as: Hum Immunol. 2019 Feb 5;80(9):633–643. doi: 10.1016/j.humimm.2019.01.010

Table 4B:

Pairwise combination

Sample Relationship HLA-A HLA-C Informative HLA-A~HLA-C
3FFE mother A*01:01:01:01+
A*24:02:01:01		 C*08:02:01:02+
C*01:02:01		 False A*01:01:01:01~
C*08:02:01:02+
A*24:02:01:01~
C*01:02:01
3FFD father A*01:01:01:01+
A*24:02:01:01		 C*04:01:01:06+
C*12:02:02		 False A*01:01:01:01~
C*12:02:02+
A*24:02:01:01~
C*04:01:01:06
4000 child A*01:01:01:01+
A*24:02:01:01		 C*01:02:01+
C*12:02:02		 False A*01:01:01:01~
C*12:02:02+
A*24:02:01:01~
C*01:02:01
3FFC child A*01:01:01:01+
A*24:02:01:01		 C*08:02:01:02+
C*04:01:01:06		 False A*01:01:01:01~
C*08:02:01:02+
A*24:02:01:01~
C*04:01:01:06
3FFF child A*01:01:01:01+
A*01:01:01:01		 C*12:02:02+
C*08:02:01:02		 True A*01:01:01:01~
C*12:02:02+
A*01:01:01:01~
C*08:02:01:02

It is not possible to build an unambiguous HLA-A~HLA-C haplotypes from children 4000 and 3FFC, because these two children and their parents have identical HLA-A genotypes. However, it is possible to build a unique haplotype set from a trio with child 3FFF. HaplObserve builds HLA-A~HLA-C haplotypes based on the trio with child 3FFF, and uses the haplotype information to build haplotypes for the remaining two children.